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Calculate emf of the half cell given below : Pt (s) | H2 (g, 2 atm) | HCI (aq, 0.02 M) Electrochemistry NEET 2026 PYQ

Calculate emf of the cell given below: Pt(s)| H2(g, 2 atm)|HCl (aq,0.02 M) Eo H2/H+= 0V (Given: 2.303RT/F= 0.059, log2= 0.3010) A) 0.109 V B) 0.035 V C) -0.035 V D) -0.109 V For the given reaction: 1/2 H₂ + 1/2 Cl₂  ⟶ HCl + 1 e⁻   H₂ +  Cl₂   ⟶ 2 HCl + 2    e⁻ [ Balanced Equation] Now the question comes, what will be the value of emf? To determine the value of emf you just simply have to use the Nernst Equation mentioned in the Chapter Electrochemistry in Class 12 NCERT chemistry book, which is: Ecell = E⁰cell - 2.303RT/nF Log [product]/[reactant]  Ecell = - 0.059/2  Log[HCl]²/[ H₂ ] Given,  2.303RT/F = 0.059 Ecell = - 0.059/2    Log[0.02]²/[ 2 ]   [ E⁰cell = 0 V]     [n = No. of electrons]  Ecell = - 0.059/2   [ Log 2 x 10⁻⁴]   Ecell = - 0.059/2   [ Log 2 + Log10⁻⁴] Ecell = - 0.059/2   [ 0.3010 - 4]   ...
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A linear harmonic oscillator has a total mechanical Energy 300J. If its potential energy at mean position is 100 J, then find kinetic energy at x = +A/√2.

Chapter: Simple Harmonic Motion
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When 1 dm³ of CO2 gas is passed over hot coke, the volume of gaseous mixture after complete reaction at STP becomes 1.4 dm³. The Composition of the gaseous mixture at STP is NEET 2026 PYQ MOLE CONCEPT

When 1 dm³ of CO2 gas is passed over hot coke, the volume of gaseous mixture after complete reaction at STP becomes 1.4 dm³. The Composition of the gaseous mixture at STP is A) 0.6 dm³ of CO, 0.8 dm³ of CO2 B) 0.8 dm³ of CO, 0.8 dm³ of CO2 C) 0.8 dm³ of CO, 0.6 dm³ of CO2 D) 0.6 dm³ of CO, 0.4 dm³ of CO2 Solution
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